Write a program to check leap year in c

In this article, you will learn different ways in C to check whether a particular year is a Leap Year or not.

A leap year is 366 days old rather than 365 days in light of the fact that February is about 29 days long instead of the normal 28 days. This additional day occurs in years which are multiples of four, i.e., 1992, 1996, 2000, 2004, 2008, 2012.

Logic for Leap Year

Most of us definitely know the logic to check for a leap year in a Gregorian calendar. These are the three rules that should be taken to identify a leap year -

The year can be evenly divided by 4,
If the year can be evenly divided by 100, it is NOT a leap year, except if;
The year is also evenly divisible by 400. Then it is a leap year.

Program to check leap year in C

In the given program, we ask the user to enter a year and assign it to a variable. Next, we use the if else statements and implement the above logic to check whether the entered year is a leap year or not.

#include <stdio.h>

int main() {
   int year;
   printf("Enter a year: ");
   scanf("%d", &year);

   // leap year if evenly divisible by 400
   if (year % 400 == 0) {
      printf("%d is a leap year.", year);
   }
   // not a leap year
   // If the year is evenly divided by 100
   // but not divisible by 400
   else if (year % 100 == 0) {
      printf("%d is not a leap year.", year);
   }
   // leap year if not divisible by 100
   // but divisible by 4
   else if (year % 4 == 0) {
      printf("%d is a leap year.", year);
   }
   // otherwise year is not leap year
   else {
      printf("%d is not a leap year.", year);
   }

   return 0;
}

Output of the above code -

Enter a year: 2020
2020 is a leap year.


Enter a year: 2021
2021 is not a leap year.

We can also write the above program as -

#include <stdio.h>

int main() {
   int year;
   printf("Enter a year: ");
   scanf("%d", &year);

   if (((year % 4 == 0) && (year % 100!= 0)) || (year%400 == 0))
      printf("%d is a leap year", year);
   else
      printf("%d is not a leap year", year);

   return 0;
}

Output of the above code:

Enter a year: 2022

2022 is not a leap year

C program to check leap year between given range

In the given example, we will find the leap years between the given range of two years.

#include <stdio.h>
#include <conio.h>

void main(){
    int i;
    int min_year,max_year;

    printf("Enter the lowest year: ");
    scanf("%d",&min_year);

    printf("Enter the highest year: ");
    scanf("%d",&max_year);

    printf("Leap years in given range are: ");
    for(i = min_year;i <= max_year; i++){
         if(((i%4==0)&&(i%100!=0))||(i%400==0))
             printf("%d ",i);
    }
    getch();
}

Output of the above code -

Enter the lowest year: 1990
Enter the highest year: 2020
Leap years in given range are: 1992 1996 2000 2004 2008 2012 2016 2020

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