Sum of n numbers in Python using Recursion

In this post, you will learn how to calculate the sum of the first n numbers in Python using recursion. Here's a simple example:

# Function to calculate the sum of first n natural numbers using recursion
def sum_of_n_numbers(n):
    if n <= 0:
        return 0
    else:
        return n + sum_of_n_numbers(n - 1)

# Example usage
n = 10
print(f"The sum of the first {n} natural numbers is: {sum_of_n_numbers(n)}")

The sum of the first 10 numbers is: 55

Code Explanation:

1. The function sum_of_n_numbers takes an integer n as input.
2. It uses a base case to check if n is less than or equal to 0, in which case it returns 0.
3. Otherwise, it returns n plus the result of calling sum_of_n_numbers with n - 1.

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