Count consonants in a string Python

Here, you will learn how to write Python program to count and display the total number of consonants present in a string. This type of logical coding question is generally asked in programming interviews or examinations. We should be aware that the perfect solution to the most fundamental coding or programming inquiries decides how we perform in an interview. There are several ways to count and display the total number of consonants present in a given string. Here, we have mentioned most of them.

Python program to count and display consonants in a string using forloop 1

Here is the Python program to count consonants present in a given string using a for loop. When the user entered the string as input, it passed through the for loop statement. If the letter is a consonant, the counter increases.

# Count consonants & vowels in a string using Python
 
vowels=0
consonants=0

# Enter an input string 
user_input = input("Enter a string: ")
 
# convert string in case insensitive
string = user_input.lower()
 
for i in string:
    if(i == 'a'or i == 'e'or i == 'i'or i == 'o'or i == 'u':
        vowels=vowels+1;
    else:
        consonants=consonants+1;
 
print("The number of vowels:",vowels);
print("\nThe number of consonant:",consonants);

Enter a string: apple
The number of vowels: 2

The number of consonant: 3

Python program to count consonants in a string using forloop 2

Here is the other way to count the total consonants present in a string using a for loop. First, we initialised the consonants with a 0 variable. When the user entered the string as input, we stored it in a variable and applied the lower() method to make it case insensitive. In programming, the vowels in the uppercase string "AEIOU" count as different characters than the vowels in the lowercase string "aeiou". Next, we have passed the string through the for loop statement and checked for each character, updating the counter accordingly. If the letter is a consonant, the counter increases.

# Count consonants in a string using Python
 
consonants=0

# Enter an input string 
user_input = input("Enter a string: ")
 
# convert string in case insensitive
string = user_input.lower()
 
for i in range(0,len(string)):  
    if string[i] not in ('a',"e","i","o","u"):  
        consonants = consonants + 1;  
 
print("The number of consonant:",consonants);

Enter a string:  ostrich is the largest bird
The number of consonants: 21

Python program to count consonants in a string using Iterative Method

Here, we have used an iterative method to count the total consonants in a string.

# Count consonants in a string using Python

# Define function to check for consonant 
def check_consonant(x): 
      
    # convert string in lowercase
    x = x.lower() 
  
    return not (x == 'a' or x == 'e' or 
                x == 'i' or x == 'o' or 
                x == 'u') 

# function to count consonants  
def countConsonants(string): 
      
    count = 0
      
    for i in range(len(string)): 
  
        # To check is character is Consonant 
        if (check_consonant(string[i])): 
            count += 1
              
    return count 
  

# Enter an input string 
user_input = input("Enter a string: ")
print("The number of consonants:", countConsonants(user_input)) 

Python program to count consonants in a string using recursive method

Recursion function is a function that is called itself. In the given Python program, we have called the recursion function to get the total number of consonants in a string input. A recursion function continues until some condition is met to prevent it. That's why we use the if statement to break the infinite recursion.

# Program to count consonants

# function to check consonant 
def check_consonant(x): 
      
    return not (x == 'a' or x == 'e' or 
                x == 'i' or x == 'o' or 
                x == 'u')
  
# Count total number of consonants from 0 to n-1 
def count_consonants(string, n): 
      
    if n == 1: 
        return check_consonant(string[0]) 
  
    return count_consonants(string, n - 1) + check_consonant(string[n-1]) 
  
  
# Enter an input string 
user_input = input("Enter a string: ")
 
# convert string in case insensitive
string = user_input.casefold()

print("The number of consonants: ",count_consonants(string, len(string))) 

Enter a string: Success is journey
The number of consonants:  12

Related Articles

Python multiline string
Local variable referenced before assignment Python
Python OpenCV Histogram of Color Image
Eye Detection Program in Python OpenCV
Find the stop words in nltk Python
Alphabet pattern programs in Python
Python remove punctuation from string
Remove character from string Python
Count vowels in a string python
Count occurrences of each character in string Python
Convert string to list Python
Python split multiple delimiters
Python program to reverse a string
Permutation of string in Python
Remove spaces from string Python
splitlines in python
Python program to sort words in alphabetical order
Python split string by comma
Remove character from string Python
Check if two strings are anagrams Python